Question

Expand by using identity-
(3x/2+1)^3

Answer 1

Answer:

$=\frac{27x^3+54x^2+36x+8}{8}$

Step-by-step explanation:

Given Equation is (3x/2 + 1)³

We know that (a + b)³ = a³ + 3a²b + 3ab² + b³

$=(\frac{3x}{2})^3+3(\frac{3x}{2})^2*1+3*\frac{3x}{2}*1^2+1^3$

$=\frac{27x^3}{8}+\frac{27x^2}{4}+\frac{9x}{2}+1$

$=\boxed{\frac{27x^3+54x^2+36x+8}{8}}$

Hope it helps!

Answer 2

Using identity
(a+b)³=a³+b³+3ab(a+b)