Math, asked by indrajchandhora35, 11 months ago

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identity. 1. (97)^3 2.(999)^3​

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Answered by harnoor92
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Answer:

  ({100 - 3)}^{3}  \\   {100}^{3}   -  {3}^{3}  - 3(100) {}^{2} (3) + 3(100)(3) {}^{2}  \\ 1000000 - 27 - 90000 + 2700 \\  1002700 - 90027 \\ 912673

hope it helps you

 {999}^{3}  \\  {(1000 - 1)}^{3}  \\  {1000}^{3}  -  {1}^{3}  - 3 {(1000)}^{2} (1) + 3(1000) ({1})^{2}  \\ 1000000000 - 1 - 3(1000000)(1) + 3000 \\ 999999999 - 3000000 + 3000 \\ 997002999

hope it helps

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