Expand by using suitable identity (4x – 3y – z )2
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Answered by
1
Answer:
ANSWER
(4x−3y−2z)
2
=[(4x−3y)−(2z)]
2
=(4x−3y)
2
−2(4x−3y)−(2z)+4z
2
=16x
2
=2×4x×3y+9y
2
−2[8xz−6y
2
]+4z
2
=16x
2
−24xy+9y
2
−16xz+12yz+4z
2
solution
Answered by
4
Step-by-step explanation:
16x²+9y²+z²-24xy+6yz-8zx
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