Question

Expand by using suitable identity (4x – 3y – z )2​
pls doit fast

Answer 1

Answer:

ANSWER

(4x−3y−2z)

2

=[(4x−3y)−(2z)]

2

=(4x−3y)

2

−2(4x−3y)−(2z)+4z

2

=16x

2

=2×4x×3y+9y

2

−2[8xz−6y

2

]+4z

2

=16x

2

−24xy+9y

2

−16xz+12yz+4z

2

solution

Answer 2

Step-by-step explanation:

16x²+9y²+z²-24xy+6yz-8zx