Question

expand each expression using algebraic identities
2. (u^v-9)^2​

Answer 1

Answer:

${u}^{2v - 18}$

Step-by-step explanation:

$( { {u}^{v - 9} )}^{2} \\ </strong>=<strong> {u}^{2 \times (v - 9)}$

by the formula :-

$( { {x}^{m}) }^{n} = {x}^{m \times n}$

(here x = u, m = v-9 and n = 2)

${u}^{2 \times (v - 9)} \\ = {u}^{2v - 18} \\ \\ hence \: ( { {u}^{v - 9} )}^{2} = {u}^{2v - 18}$

hope it helps.