Question

expand each following using suitable identities (-2x+3y+2z)^2​

Answer 1

given :- ( 2x + 3y + 2z )²

by using identity ( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ac

here a = 2x, b = 3y and c = 2z

( 2x + 3y + 2z )² = (2x)² + (3y)² + (2z)² + 2(2x)(3y) + 2(3y)(2z) + 2(2x)(2z)

= 4x² + 9y² + 4z² + 12xy + 12yz + 12xz

Answer 2

Answer:

$4x^{2} + 9y^{2} + 4z^{2} - 12xy + 12yz - 8xz$

Step-by-step explanation:

(-2x+3y+2z)^2

$(-2x)^{2} + (3y)^{2} + (2z)^{2} + 2(-2x)(3y) + 2(3y)(2z) + 2(2z)(-2x)$

$4x^{2} + 9y^{2} + 4z^{2} - 12xy + 12zy - 8xz$