Question

Expand each of the following using suitable identities: (-1/2a-1/2b+1)²

It would mean alot if you can help me with this and Homiess please don't spam​

Answer 1

Answer:

formula (a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca

(-1/2a-1/2b+c)^2=(-1/2)^2+(-1/2)^2+(1)^2+2(-1/2a)(-1/2)b+2(-1/2b)(1)+2(1)(-1/2a)

1/4a^2+1/4b^2+1+1/2ab--b-a

Answer 2

Answer:

$\huge {\red {\mathscr {Given:}}}$

${( \frac{ - 1}{2a \: - \: 1} \div 2b \: + \: 1)}^{2}$

$\huge {\red {\mathscr {Solution:}}}$

${\frac{2b \: - \: 1}{2b \: + \: 1}}^{2}$

= $\frac{{4b}^{2} + {1}^{1} - 2 \times 2b \times 1}{{4a}^{2} + {1}^{1} - 2 \times 2a \times 1}$ (can't be solved anymore so this is the answer)

pls wait, its wrong, i will correct it