Expand each of the following using suitable identities:
a) (a + 3b + c)²
PLEASE DO IT ON A ROUGH PAGE.
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We have, (2a−3b−c)²
Using identity
(a+b+c) 2 =a² +b² +c²+2ab+2bc+2ca,
we get
∴(2a−3b−c)²
=(2a)²+(−3b)²+(−c)² +2(2a)(−3b)+2(−3b)(−c)+2(−c)2a
=4a²+9b²+c²-12ab+6bc-4ac
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