Expand each of the following, using suitable identities: i) (2x-y)²
ii) (3x + 5)² - ²
iii) (x - 1/3 ) ²
iv) (4x + 5) (4x - 5)
v) (2x + 3) (2x-3)
Answers
Answer:
i) (2x-y)² = 4x² - 4xy + y²
ii) (3x + 5)²= 9x² + 30x + 25
iii) (x - 1/3 ) ² = x² - 2/3x + 1/9
iv) (4x + 5) (4x - 5) = 16x² - 25
v) (2x + 3) (2x-3) = 4x² - 9
Step-by-step explanation:
(i) :-
= (2x-y)²
= *(a-b)² = a² - 2ab + b²*
= (2x-y)² = (2x)² - 2(2x)(y) + (y)²
= (2x-y)² = 4x² - 4xy + y² (Answer)
(ii) :-
= (3x + 5)²
= *(a+b)² = a² + 2ab + b²*
= (3x + 5)²= (3x)² + 2(3x)(5) + (5)²
= (3x + 5)²= 9x² + 30x + 25 (Answer)
(iii) :-
= (x - 1/3 ) ²
= *(a-b)² = a² - 2ab + b²*
= (x - 1/3 ) ² = (x)² - 2(x)(1/3) + (1/3)²
= (x - 1/3 ) ² = x² - 2/3x + 1/9 (Answer)
(iv) :-
= (4x + 5) (4x - 5)
= *(a+b) (a-b) = a² - b²*
= (4x + 5) (4x - 5) = (4x)² - (5)²
= (4x + 5) (4x - 5) = 16x² - 25 (Answer)
(v) :-
= (2x + 3) (2x-3)
= *(a+b) (a-b) = a² - b²*
= (2x + 3) (2x-3) = (2x)² - (3)²
= (2x + 3) (2x-3) = 4x² - 9 (Answer)