expand each of the following using suitable identities X + 2 Y + 4 Z whole square
Answers
Answered by
9
Answer:
(x + 2y +
4z)²
Using identity,
(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
Here, a = x, b = 2y and c = 4z
(x + 2y + 4z)²
= x² + (2y)² +
(4z)²² + (2×x×2y) + (2×2y×4z) + (2×4z×x)
= x² +
4y² + 16z²+ 4xy + 16yz + 8xz
hope it helps u
Step-by-step explanation:
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Answered by
3
Answer:
Step-by-step explanation:
(x+2y+4z)^2
(x^2)+(4y^2)+(16z^2)+4xy+16yz+8zx
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