Question

expand expand the following​

Answer 1

Answer:(4a-b+2c)^2

=(4a-b+2c)x(4a-b+2c)

=16a^2-8ab+16ac+b^2-4bc+4c^2

Step-by-step explanation:

Answer 2

$({4a})^{2} + ( { - b}^{2} ) + ({2c)}^{2} + 2 \times 4a \times - b + 2 \times - b \times 2c + 2 \times 2c \times 4a \\ = {16a}^{2} + {b}^{2} + {4c}^{2} - 8ab - 4bc + 16ca$