Question

expand expression using algebraic identities (2s-5t)³​

Answer 1

By using the formula : (a-b)³=a³-b³-3ab(a-b)

Step-by-step explanation:

(2s-5t)³=(2s)³-(5t)³-3(2s)(5t)(2s-5t)

=8s³-125t³-30st(2s-5t)

=8s³-125t³-60s²t+150st²

Answer 2

ANSWER:

Identity used for Factorization:

$(a-b)^3 = a^3-b^3-3xy(x-y)$

Factorization:

$:=>(2s - 5t)^3 = (2s)^3 - (5t)^3 -3(2s)(5t)[2s-5t]\\\\:=>8s^3-125t^3-30st[2s-5t]\\\\=8s^3 -125t^3-60s^2t+150st^2$

CONCLUSION:

∴ The Factorized Form of $(2s - 5t)^3$ is = $8s^3 - 125t^3 - 60s^2t+150st^2$.