Question

Expand following (i)(2p + 3)(2p −4)(2p −5) (iii)(3a +1)(3a −2)(3a + 4)

Answer 1

Answer:

1. (2p + 3)(2p −4)(2p −5)

= (4p²+6p–8p –12)(2p–5)

= (4p²–2p–12)(2p–5)

= 2(2p²–p–6)(2p–5)

= 2(4p³–2p²–12p–10p²+5p+30)

= 2(4p³–12p²–7p+30)

2. (3a +1)(3a −2)(3a + 4)

= (9a²+3a–6a–2)(3a+4)

= (9a²–3a–2)(3a+4)

= (27a³–9a²–6a+36a²–12a-8)

= ( 27a³+27a²–18a–8)