Expand (ii)(x+5)(x+6)(x+4)
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0
Answer:
5+5
4+6
6+4.............
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2
Since,
(x+a)(x+b)(x+c)
= x³ + (a+b+c)x² + (ab+bc ac)x + abc -- (i)
In question, a = 5 ; b = 6 & c = 4
Put value of a, b & c in (i)
x³ + (5+6+4)x² + (30+24+20)x + 120
= x³ + 15x² + 74x + 120 ______(Ans.)
Hope it helps....
^______°
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