Question

Expand in full in a binomial theorems (a+3b) power of 5

Answer 1

Answer:

(a+3b)^5

=C(5,0)a^5 + C(5,1)a^4*3b + C(5,2)a^3*3b^2 + C(5,3)a^2*3b^3 + C(5,4)a*3b^4 + C(5,5)3b^5

=a^5+5a^4*(3b)+ 10a^3*(3b)^2+ 10a^2*(3b)^3+ 5a*(3b)^4+ (3b)^5

a^5+5a^4*3b+10a^3*9b^2+10a^2*27b^3+5a*81b^4+243b^5