expand (k+4)^3 the problem
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Let us simplify the expression, we get
(k + 4)3 = (k)3 + [ 3 ×(k)2 × (4)] + [ 3 × (k) × (4)2 ] + (4)3
By using the formula,
(a + b)3 = a3 + 3a2b + 3ab2 + b3
Here a = k, b = 4
Now, substitute the value we get
= k3 + (3 × 4)k2 + (3 × 16)k + 64
= k3 + 12k2 + 48k + 64
∴ (k + 4)3 = k3 + 12k2 + 48k + 64
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