Question

expand log(1125÷32)​

Answer 1

Answer:

log (1125/32)

= log (3 cube×5 cube/2 power 5)

=log (3 square×5 cube)- log(2 power 5)

2log3+3log5-5log2

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Step-by-step explanation:

Answer 2

Hey Mate,

Here Is Your Answer✔️

Answer:

log(1125)=2log(3)+3−3log(2)≈3.0511525225

Explanation:

It depends where you are starting from.

Suppose you know:

log(2)≈0.30102999566

log(3)≈0.47712125472

Then you can calculate a good approximation for log(1125)

1125=32⋅53=32⋅(102)3=32⋅10323

So:

log(1125)=log(32⋅10323)

=log(32)+log(103)−log(23)

=2log(3)+3log(10)−3log(2)

=2log(3)+3−3log(2)

≈2⋅0.47712125472+3−3⋅0.30102999566

≈3.0511525225

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