Expand:log (128/625)
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Step-by-step explanation:
hope it helps you...@ky
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Answer:
Given : log₁₀(128/625)
To Find : Value
Solution:
log₁₀(128/625)
= log₁₀128 - log₁₀625
= log₁₀2⁷ - log₁₀5⁴
= 7 log₁₀2 - 4 log₁₀5
= 7 log₁₀2 - 4 log₁₀(10/2)
= 7 log₁₀2 - 4 (log₁₀10 - log₁₀2)
= 7 log₁₀2 - 4 log₁₀10 + 4log₁₀2
= 11 log₁₀2 - 4 (1) ( log₁₀10 = 1)
= 11 log₁₀2 - 4
= 11(0.301) - 4 ( log₁₀2 =0.310)
= 3.311 - 4
= -0.689
log₁₀128 - log₁₀625 = -0.689
have a nice day
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