Question

Expand:log (128/625)​

Answer 1

Step-by-step explanation:

hope it helps you...@ky

Answer 2

Answer:

Given : log₁₀(128/625)

To Find : Value

Solution:

log₁₀(128/625)

= log₁₀128 - log₁₀625

= log₁₀2⁷ - log₁₀5⁴

= 7 log₁₀2 - 4 log₁₀5

= 7 log₁₀2 - 4 log₁₀(10/2)

= 7 log₁₀2 - 4 (log₁₀10 -   log₁₀2)

= 7 log₁₀2 - 4 log₁₀10 + 4log₁₀2

= 11 log₁₀2 - 4 (1)   (  log₁₀10 = 1)

= 11 log₁₀2  - 4

= 11(0.301) - 4    ( log₁₀2 =0.310)

= 3.311 - 4

= -0.689

log₁₀128 - log₁₀625 = -0.689

have a nice day