Question

expand log 128/625 with this formula log a power n=n log a

Answer 1

hello friend,
log 128/625
log [(2^7)/(5^4)]
log 2^7 / log 5^4
7 log2 / 4log5
7log2 - 4log5

Answer 2

We know that,

log aⁿ = n log a

→log 128/625

→log x/y = log x-log y

So,log 128/625 = log 128 - log 625

128 = 2×2×2×2×2×2×2 = 2^7

625 = 5×5×5×5 = 5⁴

→log 128 - log 625

→log 2^7 - log 5⁴

log aⁿ = n log a

→7 log 2 - 4 log 5

Hope it helps