Question

Expand log ( 2020) base 10

Answer 1

Answer:

3.3053

Step-by-step explanation:

$\\log_{10}2020 \\ = log_{10}(1000*2.02)\\=log_{10}10^{3} + log_{10}2.02 \\ = 3log_{10}10+ log_{10}2.02 \\ = 3*1 + .3053\\ = 3.053$

we know that

⇒$log_{a}b^{x} = xlog_{a}b\\log_{a}a = 1$

Answer 2

Answer:

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