expand log(343/125) and wite 2log 3+3 log 5-5 log 2 as single logarithm
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Step-by-step explanation:
343=7³ and 125= 5³
log(343/125)=log(7³/5³)
=log7³-log5³
=3log7-3log5
=3(log7-log5)
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2log3+3log5-5log2
=log3²+log5³-log2⁵
=log9+log125-log32
=log(9×125)/log32
=log[(9×125)/32]
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