Math, asked by gangno1, 11 months ago

expand log 343/125 .plz solve it

Answers

Answered by HappiestWriter012
32
Answer :

3( log 7 - log 5)

Step-by-step explanation :

Expansion : log(343/125)

It's a question of Logaritm, We will solve by using identities.

We know

 log( \frac{343}{125} )  \\  \\  =  log(343)  -  log(125)  \\  \\  =  log( {7}^{3} )  -  log( {5}^{3} )  \\  \\  = 3 log(7)  - 3 log(5)  \\  \\  = 3( log7 -  log5) \\  \\

FORMULAE USED :

 log( \frac{m}{n} )  =  log(m)  -  log(n)  \\  \\  \\  log( {m}^{n} )  = n log(m)
Answered by supriyaprasad1544
0

Step-by-step explanation:

Answer :

3( log 7 - log 5)

Step-by-step explanation :

Expansion : log(343/125)

It's a question of Logaritm, We will solve by using identities.

We know

\begin{gathered}log( \frac{343}{125} ) \\ \\ = log(343) - log(125) \\ \\ = log( {7}^{3} ) - log( {5}^{3} ) \\ \\ = 3 log(7) - 3 log(5) \\ \\ = 3( log7 - log5) \\ \\\end{gathered}

log(

125

343

)

=log(343)−log(125)

=log(7

3

)−log(5

3

)

=3log(7)−3log(5)

=3(log7−log5)

FORMULAE USED :

\begin{gathered}log( \frac{m}{n} ) = log(m) - log(n) \\ \\ \\ log( {m}^{n} ) = n log(m)\end{gathered}

log(

n

m

)=log(m)−log(n)

log(m

n

)=nlog(m)

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