Question

Expand log 49/64 tell me answer

Answer 1

log (7/8)^2

2 log 7/8

Therefore the expanded form of the given question is

2 log 7/8

Answer 2

The expandation of $\log \dfrac{49}{64}$ is $2\log 7-2\log 8$ or [$2(\log 7-\log 8)$.

Step-by-step explanation:

We have,

$\log \dfrac{49}{64}$

To expand $\log \dfrac{49}{64}=?$

∴ $\log \dfrac{49}{64}$

Using logarithm property,

$\log \dfrac{a}{b}=\log a-\log b$

$=\log 49-\log 64$

$=\log 7^2-\log 8^2$

Using logarithm property,

$\log a^m=m\log a$

$=2\log 7-2\log 8$ or $2(\log 7-\log 8)$

Hence, the expandation of $\log \dfrac{49}{64}$ is $2\log 7-2\log 8$ or $2(\log 7-\log 8)$.