Question

expand log root 27 X by x cube​

Answer 1

Step-by-step explanation:

$log\binom{ \sqrt{27} x}{ {x}^{3} }$

log 27x power1/2 to the base x cube

1/2*1/3log 27x to the base x.

$\frac{1}{6} . log( \binom{27x}{x} )$

$\frac{3}{6} log( \binom{3x}{x} )$

$\frac{1}{2} . log( \binom{3x}{x} )$