Question

Expand — (m + 2/3) (m - 7/3)

Answer 1

Expand — $\sf{ \bigg(m + \dfrac{2}{3}\bigg) \bigg(m - \dfrac{7}{3}\bigg)}$

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❖ Using the formula —

$\dag \; \underline{\boxed{\sf{\purple{ (x+a)(x+b) = x^2 + (a+b)x + ab }}}}$

   

$\implies \sf{ \bigg(m + \dfrac{2}{3}\bigg) \bigg(m - \dfrac{7}{3}\bigg)}$

$\implies \sf{(m)^3 + \bigg(\dfrac{+2}{3} \bigg) \times m + \bigg( \dfrac{+2}{3}\bigg) \times \bigg( \dfrac{-7}{3} \bigg) }$

$\implies \sf{m^2 + \bigg( \dfrac{ +2 - 7}{3} \bigg) \times m - \dfrac{14}{9}}$

$\implies \sf{m^2 + \bigg( \dfrac{-5}{3} \bigg) m - \dfrac{14}{9} }$

$\implies \sf{ m^2 - \dfrac{5}{3} - \dfrac{14}{9}}$

     

❖ Final Answer:

$\implies \underline{\boxed{\sf{\orange{ \sf{ \bigg(m + \dfrac{2}{3}\bigg) \bigg(m - \dfrac{7}{3}\bigg)} = m^2 - \dfrac{5}{3} - \dfrac{14}{9}}}}}$

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* ⁺◦﹆◞˚ ꒰ More to know ꒱  

   

⬩ Related Algebraic Identities :  

• (a + b)² = a² + 2ab + b²

• (a - b)² = a² - 2ab + b²

• (a + b) (a - b) = a² - b²

• (a + b)³ = a³ + 3a²b + 3ab² + b³

• (a - b)³ = a³ - 3a²b + 3ab² + b³

• (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ac

• (x + a) (x + b) = x² + (a + b)x + ab

• a³ + b³ = (a + b) (a² - ab + b²)

• a³ - b³ = (a - b) (a² + ab + b²)

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Apologies for the mistakes <3