Question

expand= (-p-r/2+q/3)^2​

Answer 1

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= ${( - p \dfrac{r}{2}+ \dfrac{q}{3})}^{2}$

= $( { p}^{2} + \dfrac{{r}^{2}}{4}+ \dfrac{{q}^{2}}{9} + \dfrac{2pr}{2} - \dfrac{2pq}{3} -\dfrac{2qr}{6} )$

= $( { p}^{2} + \dfrac{{r}^{2}}{4}+ \dfrac{{q}^{2}}{9} + pr - \dfrac{2pq}{3} -\dfrac{qr}{3} )$

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Answer 2

Answer:

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