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sin4 cos2
in a series of cosines of
multiple of .
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Then use the double angle formula derived by cos(2θ)=cos2(θ)−sin2(θ)=1−2sin2(θ)cos(2θ)=cos2(θ)−sin2(θ)=1−2sin2(θ) so
sin2(θ)=12⋅(1−cos(2θ))
sin2(θ)=12⋅(1−cos(2θ))
and you now plug into the factors of sin4(θ)sin4(θ), and use the double angle formula for cos2(2θ)cos2(2θ) to get the required answer.
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