Question

Expand sinx in powers of (x-pai/2). Here find the
value of sin 91° connect to 4 a decimal place​

Answer 1

Answer:The expansion of $sin(x)$ in powers of $(x-\frac{\pi}{2})$ using Taylor's series is [tex]sin(x) = \sum_{k \in \mathbb{N}}\frac{(x-\frac

Step-by-step explanation:

Answer 2

Answer: To expand sin(x) in powers of (x-π/2), we can use the Taylor series expansion:

$sin(x) = (x-\pi /2) - (x-\pi /2)^3/3! + (x-\pi /2)^5/5! - (x-\pi /2)^7/7! + ...$

Step-by-step explanation:

The sine x or sine theta can be defined as the ratio of the opposite side of a right triangle to its hypotenuse.

To expand sin(x) in powers of (x-π/2), we can use the Taylor series expansion:

The key points for sine are (0, 0), (π2,1), (π, 0), (3π2,−1), and (2π, 0). Graph the key points and sketch the sine curve through the points. Then continue the pattern both positive and negative.

we can use the Taylor series expansion:

$sin(x) = (x-\pi /2) - (x-\pi /2) ^3/3! + (x-\pi /2)^5/5! - (x-\pi /2)^7/7! + ...$

However, to find the value of sin(91°) to four decimal places, we can use a calculator or look up the value in a table, as the Taylor series will give an approximation, not a exact value. sin(91) is about 0.893996663600558.

for  more visit - https://brainly.in/question/48757198

#SPJ3