Expand the answer (x²
+3y)⁵
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Answer:
(x²+3y)⁵
We know that, a^(m+n) = a^m+ a^n
=(x²+3y)²+³
= (x²+3y)² × (x²+3y)³
By using Identity, (a+b)²= a²+b²+2ab and (a+b)³= a³ + b³+ 3a²b + 3ab²
=[ (x²)²+(3y)²+2(x)(3y)][(x²)³+(3y)³+3(x)²(3y)+3(x)(3y)²]
= (x⁴+9y²+6xy)(x⁶+27y³+9x²y+27xy²)
= x⁴(x⁶+27y³+9x²y+27xy²)+9y²(x⁶+27y³+9x²y+ 27xy² )+ 6xy(x⁶+27y³+9x²y+27xy²)
= x¹⁰+27xy³+9x⁶y+27x⁵y²+9x⁶y+27x⁵y²+9x⁶y²+ 243y⁵ +81x²y³+ 243xy⁴+6x⁷y+ 162xy⁴+ 54x³y²+ 162x²y³
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