Question

expand the following

Answer 1

Hi friend✋✋✋✋
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Your answer
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1.

$( \frac{1}{x} + \frac{y}{3} ) {}^{3} \\ \\ = > (\frac{1}{x} ) {}^{3} + ( \frac{y}{3} ) {}^{3} + 3 \times ( \frac{1}{x} ) \times ( \frac{y}{3} )( \frac{1}{x} + \frac{y}{3} ) \\ \\ = > \frac{1}{x {}^{3} } + \frac{y {}^{3} }{27} + \frac{y}{x} ( \frac{3 + xy}{3x} ) \\ \\ = > \frac{1}{x {}^{3} } + \frac{y {}^{3} }{27} + \frac{y}{x} \times \frac{3}{3x} + \frac{y}{x} \times \frac{xy}{3} \\ \\ = > \frac{1}{x {}^{3} } + \frac{y {}^{3} }{27} + \frac{3y}{3x {}^{2} } + \frac{xy {}^{2} }{3x}$
2.

$( \frac{4a}{5} - 2) {}^{3} \\ \\ = > ( \frac{4a}{5} ) {}^{3} - (2) {}^{3} - 3 \times \frac{4a}{5} \times 2( \frac{4a}{5} + 2) \\ \\ = > \frac{64a {}^{3} }{125} - 8 - \frac{24a}{5} ( \frac{4a}{5} + 2) \\ \\ = > \frac{64a {}^{3} }{125} - 8 - \frac{24a}{5} \times \frac{4a}{5} - \frac{24a}{5} \times 2 \\ \\ = > \frac{64a {}^{3} }{125} - 8 - \frac{96a {}^{2} }{25} - \frac{48a}{5}$
HOTE IT HELPS

Answer 2

Answer:

upper answer is right buddy