expand the following (2a+3b-4c)²
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Answer:
We know,
(x+y+z)² = x² + y² + z² + 2xy + 2yz + 2zx [Identity]
Here,
x = 2a
y = 3b
z = 4c
Putting Values in Identity, We get :
⇒ (2a + 3b + 4c)² = (2a)² + (3b)² + (4c)² + 2(2a) (3b) +2(3b) (4c)+2(4c) (2a)
= 4a² +9b² +16c² + 12ab +24bc+ 16ca
Step-by-step explanation:
hope u understood the answer
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