Question

expand the following (2a+3b-4c)² ​

Answer 1

Answer:

We know,

(x+y+z)² = x² + y² + z² + 2xy + 2yz + 2zx [Identity]

Here,

x = 2a

y = 3b

z = 4c

Putting Values in Identity, We get :

⇒ (2a + 3b + 4c)² = (2a)² + (3b)² + (4c)² + 2(2a) (3b) +2(3b) (4c)+2(4c) (2a)

= 4a² +9b² +16c² + 12ab +24bc+ 16ca

Step-by-step explanation:

hope u understood the answer