expand the following : (2x-1/3y) 3
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Answered by
0
Answer:
Step-by-step explanation:
(a-b)³ = a³-b³-3ab(a-b)
(2x-1/3y)³
=(2x-1)³/(3y)³
= [8x³-1-3(2x)(1)(2x-1)]/27y³
= (8x³-1-12x²+6x)/27y³
Answered by
0
Answer:
=8x^3-(1/27y^3)-(4x^2/y)+(2x/3y^2)
Step-by-step explanation:
(2x)^3-(1/3y)^3-3×2x×(1/3y)(2x-1/3y)
=8x^3-(1/27y^3)-2x/y(2x-1/3y)
=8x^3-(1/27y^3)-(4x^2/y)+(2x/3y^2)
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