Expand the following (2x^2 -3y)^3
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Answer:
(2^2-3y)^3
(2^2+3-3y^3)
2^5-3y^3
32-27y
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(2x²-3y)³
[by using the algebraic identities (a-b)³=a³-b³-3ab(a-b)
here, a=2x², b=3y]
=(2x²)³-(3y)³-3(2x²)(3y)(2x²-3y)
=8x⁶-27y³-18x²y(2x²-3y)
=8x⁶-27y³-36x⁴y+54x²y²
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