Math, asked by KannaB, 1 year ago

expand the following (3a+1) (3a-2) (3a+4)​

Answers

Answered by AbhijithPrakash
22

Answer:

\mathrm{Expand}\:\left(3a+1\right)\left(3a-2\right)\left(3a+4\right):\quad 27a^3+27a^2-18a-8

Step-by-step explanation:

\left(3a+1\right)\left(3a-2\right)\left(3a+4\right)

\mathrm{Expand}\:\left(3a+1\right)\left(3a-2\right)

\left(3a+1\right)\left(3a-2\right)

\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd

a=3a,\:b=1,\:c=3a,\:d=-2

=3a\cdot \:3a+3a\left(-2\right)+1\cdot \:3a+1\cdot \left(-2\right)

\mathrm{Apply\:minus-plus\:rules}

+\left(-a\right)=-a

=3\cdot \:3aa-3\cdot \:2a+1\cdot \:3a-1\cdot \:2

\mathrm{Simplify}\:3\cdot \:3aa-3\cdot \:2a+1\cdot \:3a-1\cdot \:2

3\cdot \:3aa-3\cdot \:2a+1\cdot \:3a-1\cdot \:2

3\cdot \:3aa

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:3=9

=9aa

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

aa=\:a^{1+1}

=9a^{1+1}

\mathrm{Add\:the\:numbers:}\:1+1=2

=9a^2

3\cdot \:2a=6a

1\cdot \:3a=3a

1\cdot \:2=2

=9a^2-6a+3a-2

=\left(9a^2-3a-2\right)\left(3a+4\right)

\mathrm{Expand}\:\left(9a^2-3a-2\right)\left(3a+4\right)

\left(9a^2-3a-2\right)\left(3a+4\right)

\mathrm{Distribute\:parentheses}

=9a^2\cdot \:3a+9a^2\cdot \:4+\left(-3a\right)\cdot \:3a+\left(-3a\right)\cdot \:4+\left(-2\right)\cdot \:3a+\left(-2\right)\cdot \:4

\mathrm{Apply\:minus-plus\:rules}

+\left(-a\right)=-a

=9\cdot \:3a^2a+9\cdot \:4a^2-3\cdot \:3aa-3\cdot \:4a-2\cdot \:3a-2\cdot \:4

\mathrm{Simplify}\:9\cdot \:3a^2a+9\cdot \:4a^2-3\cdot \:3aa-3\cdot \:4a-2\cdot \:3a-2\cdot \:4

9\cdot \:3a^2a+9\cdot \:4a^2-3\cdot \:3aa-3\cdot \:4a-2\cdot \:3a-2\cdot \:4

9\cdot \:3a^2a

\mathrm{Multiply\:the\:numbers:}\:9\cdot \:3=27

=27a^2a

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

a^2a=\:a^{2+1}

=27a^{2+1}

\mathrm{Add\:the\:numbers:}\:2+1=3

=27a^3

9\cdot \:4a^2=36a^2

3\cdot \:3aa=9a^2

3\cdot \:4a=12a

2\cdot \:3a=6a

2\cdot \:4=8

=27a^3+36a^2-9a^2-12a-6a-8

\mathrm{Add\:similar\:elements:}\:-12a-6a=-18a

=27a^3+36a^2-9a^2-18a-8

\mathrm{Add\:similar\:elements:}\:36a^2-9a^2=27a^2

=27a^3+27a^2-18a-8


KannaB: txs for the answer
AbhijithPrakash: NP :)
Answered by avinashkrchauhan2
0

Answer of (3a+1) (3a-2) (3a+4)

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