Question

expand the following (3x-1)(3x+2)(3x-4​

Answer 1

$\huge\underbrace\mathcal\red{ ⋆Hey \: There⋆}$

(3x-1)(3x+2)(3x-4)

= (9x^2 + 6x - 3x - 2)(3x-4)

= (9x^2 - 3x - 2)(3x-4)

= (27x^3 - 9x^2 - 6x - 36x^2 + 12x + 8)

= 27x^3 - 45x^2 + 6x + 8

Hope it helps...

Answer 2

Answer:

hope it helped u

Step-by-step explanation:

 (3x-1)(3x+2)(3x-4)

= (9x^2 + 6x - 3x - 2)(3x-4)

= (9x^2 - 3x - 2)(3x-4)

= (27x^3 - 9x^2 - 6x - 36x^2 + 12x + 8)

= 27x^3 - 45x^2 + 6x + 8

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