Math, asked by chavansakshi8, 1 year ago

expand the following - [3x+1/x] whole cube

Answers

Answered by MADHANSCTS
5
[3x+1/x]³ = 27x³ + 1/x³ + (3×9x²× \frac{1}{x} ) + 3×3x×1/x²
               = 27x³ + 1/x³ + 27x + 9/x 
Answered by ambikajana43
3

Answer:

HERE U GO

Step-by-step explanation:

I COULDN'T FIT THE SUM WITHIN 1 ATTACHMENT SO PLEASE REFER TO BOTH THE 2ND ONE IS THE CONTINUATION.

Attachments:
Similar questions