Question

Expand the following
(3x+4y)whole cube

Answer 1

Answer:

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Answer 2

Answer:

$27x {}^{3} + 64y {}^{3} + 108x {}^{2} y + 144xy {}^{2} \: is \: your \: answer$

Step-by-step explanation:

$= (3x + 4y)^{3} \\ using \: identity \: (x + y) ^{3} = x^{3} + {y}^{3} + 3xy(x + y) \\ = (3x)^{3} + (4y) ^{3 } + 3(3x)(4y)(3x + 4y) \\ = 27x^{3}+64y ^{3} + 36xy(3x + 4y) \\ = 27x {}^{3} + 64y {}^{3} +108x {}^{2}y + 144xy {}^{2} \\ i \: hope \: it \: will \: help \: you.$