Math, asked by simranpatil1717, 1 month ago

expand the following ​

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Answered by karakacharmi
1

Answer:

(3a-1/a)³

=(3a)³-(1/a)³-3(3a)(1/a)(3a-1/a)

=27a³-1/a³-9(3a-1/a)

=27a³-1/a³-27a+9/a

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