Math, asked by simranpatil1717, 4 hours ago

expand the following ​

Attachments:

Answers

Answered by karakacharmi
1

Answer:

(3a-1/a)³

=(3a)³-(1/a)³-3(3a)(1/a)(3a-1/a)

=27a³-1/a³-9(3a-1/a)

=27a³-1/a³-27a+9/a

Attachments:
Similar questions