Question

expand the following: (4a-3b-5c)²​

Answer 1

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we know, (a-b-c)² = a²+ b²+ c²+ 2ab+ 2bc+ 2ca

so using this formula,

(4a-3b-5c)² = (4a)² + (-3b)² + (-5c)² + 2(4a)(-3b)+ 2(-3b)(-5c)+ 2(-5c)(4a)

= 16a²+ 9b²+ 25c² -24ab +30bc -40ca

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