Question

expand the following.
(4a-b+2c)^2​

Answer 1

Step-by-step explanation:

ans:16 a^2 + b^2 + 4c^2 - 8ab - 4bc + 16 ac

Hope it may helps you

Answer 2

Step-by-step explanation:

Using Formula:-

$( {a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2 ab+ 2 bc+ 2ca$

Given that:-

(4a-b+2c)^2

Solution:-

$= {(4a)}^{2} + ( { - 1b)}^{2} + ( {2c})^{2} + 2.4a - 1b + 2.( - 1b) . 2c + 2.2c.4a \\ = > {16a}^{2} + {b}^{2} + {4c}^{2} - 8ab - 4bc + 16ac$