Math, asked by VεnusVεronίcα, 7 hours ago

Expand the following by binomial expansion :
• (a+b)⁵
• (2+x)⁷
• (101)¹⁰¹
• (1.0001)¹⁰⁰
• (a+b)³

Answers

Answered by vatsalpal13jun2009
8

Answer:

• a⁵ + 5a⁴b + 10a³b² + 10a²b³ + 5ab⁴ + b⁵

• 128 + 896x\\ + 1344x^{2} + 1120x^{3} + 560x^{4} + 168x^{5} + 14x^{6} + x^{7}

• 2.73186196 × 10^{202}

• 1

a^{3} + 3a²b + 3ab² + b^{3}

Answered by Anonymous
24

Hey there is your required answer @VenusVeronica..

Questions:-

• ( a + b )⁵

• ( 2 + x )⁷

• ( 101 )¹⁰¹

• ( 1.0001 )¹⁰⁰

• ( a + b )³

Answers:-

Please refer to attachment..

  • It is answered by me as you can see at top/bottom, my username.

  • Note:- If a term has power 3 then we will apply formula =  ^{n}C_{0} × a^{n} × b⁰ + ^{n}C_{1} × a^{n - 1} × b¹ + ^{n}C_{2} × a^{n - 2} × b² + ^{n}C_{3} × a^{n - 3} × b³

  • Note:- If a term has power 5 then we will apply formula =  ^{n}C_{0} × a^{n} × b⁰ + ^{n}C_{1} × a^{n - 1} × b¹ + ^{n}C_{2} × a^{n - 2} × b² + ^{n}C_{3} × a^{n - 3} × b³ + ^{n}C_{4} × a^{n - 4} × b⁴ + ^{n}C_{5} × a^{n - 5} × b⁵ .

  • Note:- for power 7 =  ^{n}C_{0} × a^{n} × b⁰ + ^{n}C_{1} × a^{n - 1} × b¹ + ^{n}C_{2} × a^{n - 2} × b² + ^{n}C_{3} × a^{n - 3} × b³ + ^{n}C_{4} × a^{n - 4} × b⁴ + ^{n}C_{5} × a^{n - 5} × b⁵ + ^{n}C_{6} × a^{n - 6} × b⁶ + ^{n}C_{7} × a^{n - 7} × b⁷ .

  • Please note that - n refers to power value, • means multiplication.

  • Note :-  ^{n}C_{Base \: power} = \dfrac{n}{Base \: power \:value × ( n - Base \: power \: value )}

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# i have done direct multiplication and addition ( hope u will understand )..

#Report above answer,, it is bad!!

#Answered by class 8th student..

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