Question

Expand the following by using identities. (2x-y+2z)^2​

Answer 1

Answer:

hii!!!

given :- ( 2x + 3y + 2z )²

by using identity ( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ac

here a = 2x, b = 3y and c = 2z

( 2x + 3y + 2z )² = (2x)² + (3y)² + (2z)² + 2(2x)(3y) + 2(3y)(2z) + 2(2x)(2z)

= 4x² + 9y² + 4z² + 12xy + 12yz + 12xz

Answer 2

Answer:

4x^2 + y^2 + 4z^2 - 4xy - 4yz + 8zx

Step-by-step explanation:

Using identity:

(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca

Here, a = 2x, b = -y and c = 2z

So,

(2x-y+2z)^2 = (2x)^2 + (-y)^2 + (2z)^2 + 2(2x)(-y) + 2(-y)(2z) + 2(2z)(2x)

4x^2 + y^2 + 4z^2 - 4xy - 4yz + 8zx

Hence,

(2x-y+2z)^2 = 4x^2 + y^2 + 4z^2 - 4xy - 4yz + 8zx