Question

expand the following expression question no 8​

Answer 1

Answer:

(8x^3) + (1/9x^3) + (4x^2+1/3x)

Answer 2

Answer:

$= > ({2x + \frac{1}{3x} })^{3}$

$= > { (\frac{6 {x}^{2} + 1}{3x} )}^{3}$

On using below identity,

$= > { (x + y)}^{3} = {x}^{3} + + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3}$

$= > \frac{216 {x}^{6} + 108 {x}^{3} + 18 {x}^{2} + 1 }{27 {x}^{3} }$

Hope this answer helps you ^ _ ^ !