expand the following log 343 by 125
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Hi ,
log ( 343/125 )
= log ( 7³/5³ )
= log ( 7/5 )³
= 3 log ( 7/5 )
************************
Since ,
log a^n = n log a
*****************************
= 3 [ log 7 - log 5 ]
[ Since ,
log ( m/n ) = log m - log n ]
= 3log 7 - 3 log 5
I hope this helps you.
: )
log ( 343/125 )
= log ( 7³/5³ )
= log ( 7/5 )³
= 3 log ( 7/5 )
************************
Since ,
log a^n = n log a
*****************************
= 3 [ log 7 - log 5 ]
[ Since ,
log ( m/n ) = log m - log n ]
= 3log 7 - 3 log 5
I hope this helps you.
: )
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