Expand the following log
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Asked on December 30, 2019 by
Aayush Veerwal
If a
x
=b
y
=c
z
& y
2
=xz, then the value of log
b
a will be
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ANSWER
Leta
x
=b
y
=c
z
=P
log
a
P=x
log
b
P=y
log
c
P=z
y
2
=xz
So
log
b
P⋅log
b
P=log
a
Plog
c
P
Assuming base P, we get
logb
logP
×
logb
logP
=
loga
logP
logc
logP
So we can write
logb
1
logb
1
=
loga
1
logc
1
logb
loga
=
logc
logb
log
b
a=log
c
b
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