Question

expand the following number:-
(40+7)³​

Answer 1

Answer:

$(x + y) ^{3} = {x}^{3} + {y}^{3} + 3 {x}^{2} y + 3x {y}^{2} \\ {40}^{3} + {7}^{3} + 3 \times {40}^{2} \times 7 + 3 \times 40 + {7}^{2} \\ = 107423$

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