Math, asked by spacelover123, 9 months ago

Expand the following using exponents. (i) 0.0523 (ii) 32.005

Answers

Answered by masterbrain123
149

Answer:

1)0.0523 =5*10^{-1} + 2*10x^{-2} + 3*10x^{-3} \\32.005 =3*10^{1} +2*10x^{0} + 5*10x^{-3}

Answered by Agastya0606
65

Given:

(i) 0.0523 (ii) 32.005

To find:

The expanded form of given decimals using exponents.

Solution:

(i) 0.0523

The place value of 5 is

 \frac{5}{100}  = 5 \times  {10}^{ - 2}

Similarly,

the place value of 2 is

 \frac{2}{1000}  = 2 \times  {10}^{ - 3} the place value of 3 is

 \frac{3}{10000}  = 3 \times  {10}^{ - 4}

So,

The expanded form of 0.0523 is

 = 5 \times  {10}^{ - 2}  + 2 \times  {10}^{ - 3}  + 3 \times  {10}^{ - 4}

(ii) 32.005

The given decimal number 32.005 can be written as 32 + 0.005

Now,

Proceeding same as in (i),

the place value of 3 is

 30 = 3 \times  {10}^{1}

The place value of 2 is

2 = 2 \times  {10}^{0}

The place value of 5 is

 \frac{5}{1000}  = 5 \times  {10}^{ - 3}

So,

The expanded form of 32.005 is

3 \times  {10}^{1}  + 2 \times  {10}^{0}  + 5 \times  {10}^{ - 3}

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