Question

expand the following using suitable identities (2 − 3) cube

Answer 1

Answer:

ANSWER

We need to expand (2a−3b)

3

We know suitable identity is (x−y)

3

=x

3

−3x

2

y+3xy

2

+y

3

Here x=2a and y=3b

Therefore, value of (2a−3b)

3

is

=(2a)

3

−3(2a)

2

(3b)+3(2a)(3b)

2

−(3b)

3

=8a

3

−36a

2

b+54ab

2

−27b

3

Step-by-step explanation:

Please mark as brainalist and like and follow

Answer 2

Answer:(2-3)^3=(-1)^3=-1