Expand the following using suitable identity :
i) (x + 2y - 4z)2
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Answered by
2
Answer:
We need to expand (x+2y+4z)
2
We know appropriate identity (x+y+z)
2
=x
2
+y
2
+z
2
+2xy+2yz+2xz
Therefore, the value of (x+2y+4z)
2
is
=x
2
+(2y)
2
+(4z)
2
+2(x)(2y)+2(2y)(4z)+2(x)(4z)
=x
2
+4y
2
+16z
2
+4xy+16yz+8xz
Answered by
2
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