Math, asked by Aashifa1, 1 year ago

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expand the following using suitable identity . the question is in the attachment photo!!! do it with each and every steps.✍✍✍✍✍✍✍✍

Attachments:

Aashifa1: I will ask you how I am looking
Aashifa1: I didn't ask you how I am looking
Aashifa1: fool

Answers

Answered by anonymous64
2
<b>Heya mate. (^_-). Solutions below.
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(ii)

• (3a - 4b)³

=>>> Using identity : (a - b)³ = a³ - b³ - 3ab(a - b), we get,

= [ (3a)³ - (4b)³ - (3 × 3a × 4b)(3a - 4b) ]

= [ 27a³ - 64b³ - 36ab(3a - 4b)]

= 27a³ - 64b³ - 108a²b + 144ab²

===========================

(iii)

• (x + 1/y)³

=>>> Using identity : (a + b)³ = a³ + b³ + 3ab(a + b), we get,

= [ (x)³ + (1/y)³ + (3 × x × 1/y)(x + 1/y) ]

= [ x³ + 1/y³ + 3x/y (x + 1/y) ]

= x³ + 1/y³ + 3x²/y + 3x/y²

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(iv)

• (a + 1/a)³

=>>> Using identity : (a + b)³ = a³ + b³ + 3ab(a + b), we get,

= [ (a)³ + (1/a)³ + (3 × a × 1/a)(a + 1/a) ]

= [ a³ + 1/a³ + 3 (a + 1/a) ]

= a³ + 1/a³ + 3a + 3/a

<marquee>Hope the answers help you.</marquee>

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Thank you.. ;-)

Aashifa1: brilliant
Aashifa1: thank you for giving me this answer
Aashifa1: what is your problem
anonymous64: Thanks... @aashifa... ^_^
anonymous64: Hey, @abhilashsingh, stop this nonsence
Aashifa1: yes
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