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expand the following using suitable identity . the question is in the attachment photo!!! do it with each and every steps.✍✍✍✍✍✍✍✍
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Aashifa1:
I will ask you how I am looking
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(ii)
• (3a - 4b)³
=>>> Using identity : (a - b)³ = a³ - b³ - 3ab(a - b), we get,
= [ (3a)³ - (4b)³ - (3 × 3a × 4b)(3a - 4b) ]
= [ 27a³ - 64b³ - 36ab(3a - 4b)]
= 27a³ - 64b³ - 108a²b + 144ab²
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(iii)
• (x + 1/y)³
=>>> Using identity : (a + b)³ = a³ + b³ + 3ab(a + b), we get,
= [ (x)³ + (1/y)³ + (3 × x × 1/y)(x + 1/y) ]
= [ x³ + 1/y³ + 3x/y (x + 1/y) ]
= x³ + 1/y³ + 3x²/y + 3x/y²
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(iv)
• (a + 1/a)³
=>>> Using identity : (a + b)³ = a³ + b³ + 3ab(a + b), we get,
= [ (a)³ + (1/a)³ + (3 × a × 1/a)(a + 1/a) ]
= [ a³ + 1/a³ + 3 (a + 1/a) ]
= a³ + 1/a³ + 3a + 3/a
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Thank you.. ;-)
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