Question

expand the following
(x-y/3)³

Answer 1

Hi...

here is your answer:

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${ (\frac{x - y}{3}) }^{3}$

= $\frac{ {(x - y)}^{3} }{ {3}^{3} }$

✔ ${(x - y)}^{3} = {x}^{3} - {y}^{3} - 3 {x}^{2}y + 3x {y}^{2}$

= $\frac{ \: {x}^{3} - {y}^{3} - 3 {x}^{2}y + 3x {y}^{2} \ }{27}$

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